{ "cells": [ { "cell_type": "code", "execution_count": 1, "metadata": {}, "outputs": [], "source": [ "with open('1/input', 'r') as f:\n", " data = f.readlines()\n" ] }, { "cell_type": "code", "execution_count": 2, "metadata": {}, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "2378066\n" ] } ], "source": [ "left = []\n", "right = []\n", "distances = []\n", "for line in data:\n", " a, b = map(int, line.split())\n", " left.append(a)\n", " right.append(b)\n", "\n", "left = sorted(left)\n", "right = sorted(right)\n", "\n", "for i in range(len(left)):\n", " distances.append(abs(left[i] - right[i]))\n", " \n", "print(sum(distances))" ] }, { "cell_type": "code", "execution_count": 3, "metadata": {}, "outputs": [], "source": [ "#write a function that returns the amount of value existing in the 'right' list\n", "def count_occurence(value):\n", " return sum([ True for x in right if x == value ])\n" ] }, { "cell_type": "code", "execution_count": 4, "metadata": {}, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "18934359\n" ] } ], "source": [ "print(sum([count_occurence(x)*x for x in left]))" ] } ], "metadata": { "kernelspec": { "display_name": "Python 3 (ipykernel)", "language": "python", "name": "python3" }, "language_info": { "codemirror_mode": { "name": "ipython", "version": 3 }, "file_extension": ".py", "mimetype": "text/x-python", "name": "python", "nbconvert_exporter": "python", "pygments_lexer": "ipython3", "version": "3.12.7" } }, "nbformat": 4, "nbformat_minor": 2 }