95 lines
1.8 KiB
Plaintext
95 lines
1.8 KiB
Plaintext
{
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"cells": [
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{
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"cell_type": "code",
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"execution_count": 1,
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"metadata": {},
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"outputs": [],
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"source": [
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"with open('1/input', 'r') as f:\n",
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" data = f.readlines()\n"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 2,
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"metadata": {},
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"outputs": [
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{
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"name": "stdout",
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"output_type": "stream",
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"text": [
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"2378066\n"
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]
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}
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],
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"source": [
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"left = []\n",
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"right = []\n",
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"distances = []\n",
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"for line in data:\n",
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" a, b = map(int, line.split())\n",
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" left.append(a)\n",
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" right.append(b)\n",
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"\n",
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"left = sorted(left)\n",
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"right = sorted(right)\n",
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"\n",
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"for i in range(len(left)):\n",
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" distances.append(abs(left[i] - right[i]))\n",
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" \n",
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"print(sum(distances))"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 3,
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"metadata": {},
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"outputs": [],
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"source": [
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"#write a function that returns the amount of value existing in the 'right' list\n",
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"def count_occurence(value):\n",
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" return sum([ True for x in right if x == value ])\n"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 4,
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"metadata": {},
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"outputs": [
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{
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"name": "stdout",
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"output_type": "stream",
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"text": [
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"18934359\n"
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]
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}
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],
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"source": [
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"print(sum([count_occurence(x)*x for x in left]))"
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]
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}
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],
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"metadata": {
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"kernelspec": {
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"display_name": "Python 3 (ipykernel)",
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"language": "python",
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"name": "python3"
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},
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"language_info": {
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"codemirror_mode": {
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"name": "ipython",
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"version": 3
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},
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"file_extension": ".py",
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"mimetype": "text/x-python",
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"name": "python",
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"nbconvert_exporter": "python",
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"pygments_lexer": "ipython3",
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"version": "3.12.7"
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}
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},
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"nbformat": 4,
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"nbformat_minor": 2
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}
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