added hydrogentest.py
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18
hydrogentest.py
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18
hydrogentest.py
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#!/bin/python3
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a="ksabvdkbvksajbvkjsabvkjsabvkjabsvkjsabvbvghahfksajfkjhcxvsLHREFIsdfsdfsdfasdfasdfasfd"
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b="kucasdhkausughaksdflsad iajfdaslfdlgajldsag asldivclsadgnaksndglkasdjasdvc"
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def longest_common_substring(s1, s2):
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m = [[0] * (1 + len(s2)) for i in range(1 + len(s1))]
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longest, x_longest = 0, 0
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for x in range(1, 1 + len(s1)):
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for y in range(1, 1 + len(s2)):
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if s1[x - 1] == s2[y - 1]:
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m[x][y] = m[x - 1][y - 1] + 1
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if m[x][y] > longest:
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longest = m[x][y]
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x_longest = x
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else:
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m[x][y] = 0
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return s1[x_longest - longest: x_longest]
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print(longest_common_substring(a, b))
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